# Copyright (c) ZeroC, Inc.

# slice2py version 3.8.1

from __future__ import annotations
import IcePy


PermissionLinkChannel = 128
"""
Link this channel. You need this permission in both the source and destination channel to link channels, or in either channel to unlink them.

Notes
-----
    The Slice compiler generated this constant from Slice constant ``::MumbleServer::PermissionLinkChannel``.
"""

__all__ = ["PermissionLinkChannel"]